Câu 1:

a) 4Al + 3O₂ --t^o--> 2Al₂O₃

b) 2Fe + 6H₂SO₄ --> Fe₂(SO₄)₃ + 3SO₂ +6 H₂O

c) Fe₃O₄ + 10HNO₃ --> 3Fe(NO₃)₃ + NO₂ + 5H₂O

d) \(10Al+38HNO_3->10Al\left(NO_3\right)_3+2NO+3N_2O+19H_2O\)

\(\dfrac{30.n_{NO}+44.n_{N_2O}}{n_{NO}+n_{N_2O}}=19,2.2=38,4=>\dfrac{n_{NO}}{n_{N_2O}}=\dfrac{2}{3}\)

e) \(\left(5x-2y\right)M+\left(6nx-2ny\right)HNO_3->\left(5x-2y\right)M\left(NO_3\right)_n+nN_xO_y+\left(3nx-ny\right)H_2O\)

1)

$Zn^0 \to Zn^{2+} + 2e$   x3
$N^{+5} + 3e \to N^{+2}$  x2

$3Zn + 8HNO_3 \to 3Zn(NO_3)_2 + 2NO + 4H_2O$

2)

\(Al^0 \to Al^{3+} + 3e\)    x2

\(S^{+6} + 2e\to S^{+4}\)    x3

$2Al + 6H_2SO_4 \to Al_2(SO_4)_3 + 3SO_2 + 6H_2O$

3)

\(Cr^{+6} + 3e \to Cr^{+3}\)  x1

\(Fe^{+2} \to Fe^{+3} + 1e\)  x3

$K_2Cr_2O_7 + 6FeSO_4 + 7H_2SO_4 \to 3Fe_2(SO_4)_3 + Cr_2(SO_4)_3 + K_2SO_4 + 7H_2O$

4)

\(Pb^{+4} + 2e \to Pb^{+2}\\ \)  x1

\(2Cl^- \to Cl_2 + 2e\)    x1

$PbO_2 + 4HCl \to PbCl_2 + Cl_2 + 2H_2O$

5)

$2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2$

6)

\((FeCu_2S_2)^0 \to Fe^{+3} + 2Cu^{+2} + 2S^{+4} + 15e\) x4

\(O_2 + 4e \to 2O^{-2}\)  x15

$4FeCu_2S_2 + 15O_2 \xrightarrow{t^o} 2Fe_2O_3 + 8CuO + 8SO_2$

1, 4Mg+ 10HNO₃ ------> 4Mg(NO₃)₂+N₂O + 5H₂O

2, 10Al+ 36HNO₃ ------>10Al(NO₃)₃+3N₂+ 18H₂O

3, 4Mg+ 10HNO₃ --------> 4Mg(NO₃)₂+NH₄NO₃+ 3H₂O

4, 3Fe₃O₄+ 28HNO₃ ------->.9Fe(NO₃)₃+NO + 14H₂O

5, 2FeS+ 10H₂SO₄ đặc------> Fe₂(SO₄)₃ + 9SO₂ + 10H₂O

6, FeS₂+ 18HNO₃ đặc -------> Fe(NO₃)₃ + 15NO₂ + 2H₂SO₄ + 7H₂O

4 ý cuối :

1)

Cu + 2H2SO4→ CuSO4+ SO2+2H2O

→ +2e║ x1

+2e → ║ x1

2)

2Al+ 4H2SO4→ Al2(SO4)3+ S+ 4H2O

2→2 +6e║x1

+6e→ ║x1

3)

4Zn +5H2SO4→ 4ZnSO4+ H2S+ 4H2O

+2e ║x4

+8e → ║x1

4)

8Fe+ 15H2SO4→ 4Fe2(SO4)3+3H2S+ 12H2O

2→ 2+6e║x4

+8e → ║x3

6 ý đầu

1.\(\overset{-3}{4NH_2}+\overset{0}{5O_2}\rightarrow\overset{+2+6}{4NO}+\overset{-2}{6H_2O}\)

4 X \(||\) N^-3 + 5e → N⁺²

5 X \(||\) 2O⁰ + 4e → 2O^-2

2.\(\overset{-3}{4NH3}+\overset{0}{3O_2}\rightarrow\overset{0}{2N_2}+\overset{-2}{6H_2O}\)

2 X \(||\) 2N^-3 + 6e → 2N⁰

3 X \(||\) 2O⁰ + 4e → 2O^-2

3.\(\overset{0}{3Mg}+\overset{+5}{8NO_3}\rightarrow\overset{+2}{3Mg\left(NO_3\right)_2}+\overset{+2}{2NO}+\overset{ }{4H_2O}\)

3 X \(||\) Mg⁰ → Mg⁺² + 2e

2 X \(||\) N⁺⁵ + 3e → N⁺²

4.\(\overset{0}{Al}+\overset{+5}{6NO_3}\rightarrow\overset{+3}{Al\left(NO_3\right)_3}+\overset{+4}{3NO_2}+\overset{ }{3H_2O}\)

1 X \(||\) Al⁰ → Al⁺³ + 3e

3 X \(||\) N⁺⁵ + 1e → N⁺⁴

5.\(\overset{0}{Zn}+\overset{+5}{4HNO_3}\rightarrow\overset{+3}{Fe\left(NO_3\right)_3}+\overset{+2}{NO}+\overset{ }{2H_2O}\)

1 X \(||\) Zn⁰ → Mg⁺² + 2e

2 X \(||\) N⁺⁵ + 3e → N⁺⁴

6.\(\overset{0}{Fe}+\overset{+5}{4HNO_3}\rightarrow\overset{+3}{Fe\left(NO_3\right)_3}+\overset{+2}{NO}+\overset{ }{2H_2O}\)

1 X \(||\) Fe0 → Fe+3 + 3e

1 X \(||\) N+5 + 3e → N+2

24.

xFe^+2y/x --------------> xFe⁺³ + (3x - 2y)e (x3)

N^{+ 5} + 3e -------------> N⁺² (x(3x-2y))

=> 3xFe^+2y/x + (3x-2y)N⁺⁵ -----> 3xFe⁺³ + (3x-2y)N⁺²

Vậy pư cân bằng như sau:

3Fe_xO_y + (12x - 2y)HNO₃ ----> 3xFe(NO₃)₃ + (3x-2y)NO + (6x-y)H₂O

25.

xFe^+2y/x --------------> xFe⁺³ + (3x - 2y)e -----------------(x1)

N^{+ 5} + 1e -------------> N⁺⁴ ----------------------- (x(3x-2y))

=> xFe^+2y/x + (3x-2y)N⁺⁵ -----> xFe⁺³ + (3x-2y)N⁺²

Vậy pư cân bằng như sau:

Fe_xO_y + (6x - 2y)HNO₃ ----> xFe(NO₃)₃ + (3x-2y)NO₂ + (3x-y)H₂O

26.

2xFe^+2y/x --------------> 2xFe⁺³ + (6x - 4y)e -----------------(x1)

S^{+ 6} + 2e -------------> S⁺⁴ ----------------------- (x(3x-2y))

=> 2xFe^+2y/x + (3x-2y)S⁺⁶ -----> 2xFe⁺³ + (3x-2y)S⁺⁴

Vậy pư cân bằng như sau:

2Fe_xO_y + (6x - 2y)H₂SO₄ ---> xFe₂(SO₄)₃ + (3x-2y)SO₂ + (6x-2y)H₂O

1) 10Al + 36HNO₃ → 10Al(NO₃)₃ + 18H₂O + 3N₂

Al + 4HNO₃ → Al(NO₃)₃ + 2H₂O + NO

Al + 6HNO₃ → Al(NO₃)₃ + 3H₂O + 3NO₂

8Al + 30HNO₃ → 8Al(NO₃)₃ + 9H₂O + 3NH₄NO₃

2) 5Cu + 12HNO₃ → 5Cu(NO₃)₂ + 6H₂O + N₂

3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 4H₂O + 2NO

Cu + 4HNO₃ → Cu(NO₃)₂ + 2H₂O + 2NO₂

4Cu + 10HNO₃ → 4Cu(NO₃)₂ + 3H₂O + NH₄NO₃

1.10Al+36HNO₃=>10Al(NO₃)₃+18H₂O+3N₂

Al+4HNO₃=>Al(NO₃)₃+2H₂O+NO

Al+6HNO₃=>Al(NO₃)₃+3H₂O+3NO₂

8Al+30HNO₃=>8Al(NO₃)₃+9H₂O+3NH₄NO₃

2.5Cu+12HNO₃=>5Cu(NO₃)₂+6H₂O+N₂(Cái pt này mình k chắc chắn vì mình chưa từng thấy pt nào như vậy cả mong bạn thông cảm )

3Cu+8HNO₃=>3Cu(NO₃)₂+4H₂O+2NO

Cu+4HNO₃=>Cu(NO₃)₂+2H₂O+2NO₂

4Cu+10HNO₃=>4Cu(NO₃)₂+3H₂O+NH₄NO₃(pt này giống pt trên nha bạn)

@Cẩm Vân Nguyễn Thị cô nhận xét bài làm này cho em đc k cô ???

1) 10Al + 36HNO3 => 10Al(NO3)3 + 18H2O + 3N2

Al + 4HNO3 => Al(NO3)3 + 2H2O + NO

Al + 6HNO3 => Al(NO3)3 + 3H2O + 3NO2

8Al + 30HNO3 => 8Al(NO3)3 + 9H2O +3 NH4NO3

2) 5Cu + 12HNO3 => 5Cu(NO3)2 + 6H2O + N2

3Cu + 8HNO3 => 3Cu(NO3)2 + 4H2O + 2NO

Cu + 4HNO3 => Cu(NO3)2 + 2H2O + 2NO2

4Cu + 10HNO3 => 4Cu(NO3)2 + 3H2O + NH4NO3

1) Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O

2) 2FeO + 4H₂SO₄ → Fe₂(SO₄)₃ + SO₂ + 4H₂O

3) Fe₃O₄ + 10HNO₃ → 3Fe(NO₃)₃ + NO₂ + 5H₂O

4) 8Fe + 27HNO₃ → 8Fe(NO₃)₃ + 3NH₃ + 9H₂O

mình ghi số cân bằng thôi nhaa, 3Mg +8HNO3 -> 3(Mg(NO3)2+2NO+4H2O

b, Fe+6H2SO4 -> Fe2(SO4)3+3SO2 + 6H2O

c, 4Mg + 5H2SO4 -> 4MgSO4 + H2S + 4H2O

d, 8Al +30 HNO3 -> 8Al(NO3)3 + 3NH4NO3 + 9H2O

e, 6FeCO3 + 10H2SO4 -> 3Fe2(SO4)3 +S+ 6CO2 +10H2O

f, 8Fe3O4 +74HNO3 -> 24Fe(NO3)3 + N2O + 37H2O

g, 8Al +30HNO3 -> 8Al(NO3)3 + 3N2O + 15H2O

h,10FeSO4 + 8H2SO4 +2KMnO4 -> 5Fe2(SO4)3 + 2MnSO4 + K2SO4 +8H2O

i,2KMnO4 +16 HCl ->2 KCl + 2MnCl2 + 5Cl2 + 8H2O

j,K2Cr2O7 +14HCl -> 2KCl + 2CrCl3 + 3Cl2 + 7H2O

1) 3Cu + 8HNO₃ -----> 3Cu(NO₃)₂ + 2NO + 4H₂O

2) 4FeS₂ + 11O₂ ------> 2Fe₂O₃ + 8SO₂

3) 5Zn + 12HNO₃ ------> 5Zn(NO₃)₂ + N₂ + 6H₂O

4) CH₄ + 2O₂ -------> CO₂ + 2H₂O

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